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Laws of Motion NEET Notes: Complete Guide with Formulas & Solved Examples

Laws of Motion
for NEET Physics

Master Newton's laws, inertia, momentum, friction, and dynamics of systems — the core of mechanics, explained for NEET aspirants.

Newton's Laws Inertia & Momentum Friction Free Body Diagram Dynamics
📌 What you'll learn: NEET-level problem solving • All essential formulas • Step-by-step numericals • Quick revision hacks

🔍 Detailed concept explanation

⚡ 1. Newton's First Law (Law of Inertia)

Every body continues in its state of rest or uniform motion unless acted upon by an external net force. Inertia is the property of mass to resist change in motion. Mass is a measure of inertia.

📈 2. Newton's Second Law

The rate of change of momentum of a body is directly proportional to the applied force and takes place in the direction of the force. Mathematically: F = dp/dt = ma (for constant mass). This is the fundamental equation of motion.

🔄 3. Newton's Third Law

To every action, there is an equal and opposite reaction. Forces always occur in pairs acting on two different bodies. Action-reaction pairs do not cancel each other because they act on different objects.

📦 4. Free Body Diagram (FBD)

A diagram showing all forces acting on a body. Crucial for solving problems: isolate the body, identify all forces (gravity, normal, tension, friction, applied forces), and resolve into components.

🧱 5. Friction

Force that opposes relative motion. Static friction (fs ≤ μsN) prevents motion, kinetic friction (fk = μkN) acts during motion. μs > μk. Angle of friction = tan⁻¹(μ).

⛓️ 6. Dynamics of connected systems

For multiple masses connected by strings/pulleys, draw FBD for each mass, apply F = ma, and solve simultaneous equations. Tension in massless strings is constant over ideal pulleys.

📋 Complete formula sheet

Newton's second law Fnet = ma
(vector form: ΣF = ma)
Momentum p = mv
Impulse I = Δp = FavgΔt
Friction fs,max = μsN
fk = μkN
Connected bodies For two masses on pulley: a = (m₁–m₂)g/(m₁+m₂); T = (2m₁m₂)g/(m₁+m₂)
QuantityFormula / Relation
WeightW = mg
Normal force on inclineN = mg cosθ
Acceleration on rough inclinea = g(sinθ – μkcosθ)
Angle of reposeθ = tan⁻¹(μs)
Minimum force to move blockFmin = μsmg / √(1+μs²) (pulling at optimal angle)

✏️ Solved NEET-level examples

Example 1 (Second law / FBD)

A 5 kg block is pulled on a horizontal surface with a force of 20 N at 30° above horizontal. If μk = 0.2, find acceleration. (g = 10 m/s²)

1 Resolve force: Fx = 20 cos30° = 20×0.866 = 17.32 N; Fy = 20 sin30° = 10 N upward.
2 Normal force N = mg – Fy = 5×10 – 10 = 40 N.
3 Friction fk = μkN = 0.2×40 = 8 N.
4 Net horizontal force = Fx – fk = 17.32 – 8 = 9.32 N. a = Fnet/m = 9.32/5 = 1.86 m/s².

Example 2 (Connected masses)

Two masses 4 kg and 2 kg are connected by a string over a frictionless pulley. Find acceleration and tension. (g = 10 m/s²)

1 Let heavier mass (4 kg) descend. Equations: 4g – T = 4a; T – 2g = 2a.
2 Add equations: 4g – 2g = 6a ⇒ 2g = 6a ⇒ a = 20/6 = 3.33 m/s².
3 From second eq: T = 2g + 2a = 20 + 2×3.33 = 26.66 N.

Example 3 (Friction on incline)

A 2 kg block slides down a 37° incline with μk = 0.3. Find acceleration and time to slide 4 m from rest. (g = 10 m/s², sin37=0.6, cos37=0.8)

1 Parallel component: mg sinθ = 2×10×0.6 = 12 N. Normal N = mg cosθ = 20×0.8 = 16 N.
2 Friction fk = μkN = 0.3×16 = 4.8 N. Net force down = 12 – 4.8 = 7.2 N.
3 a = F/m = 7.2/2 = 3.6 m/s². Using s = ½at², t = √(2×4/3.6) = √(8/3.6) = √2.22 ≈ 1.49 s.

📈 Important graphs & key points

  • F vs a : straight line slope = mass
  • Friction vs applied force : static region linear up to max, then kinetic constant
  • Tension in rope over pulley : same on both sides if massless & frictionless
  • Spring force : F = –kx (restoring)

⭐ Always draw FBD first. For systems, choose consistent sign convention (direction of acceleration).

⚡ Quick revision box

1st law – inertia, 2nd law – F=ma, 3rd law – action-reaction on different bodies
Friction types – static (self-adjusting), kinetic (constant μkN)
Connected motion – same acceleration for system, different tensions in complex setups
Incline – resolve g into components: g∥ = g sinθ, g⟂ = g cosθ

⚠️ Common mistakes to avoid

  • Forgetting that action-reaction pairs act on different bodies, so they don't cancel in same FBD.
  • Using f = μsN as actual force before reaching maximum static friction.
  • Incorrect normal force on incline (not always mg; if other vertical forces exist, adjust).
  • Assuming tension is same in strings when pulley has mass or friction.
  • Not resolving forces into components along acceleration direction.

🧠 Exam strategy tips

  • Always start with a clean FBD – label all forces.
  • Pick a coordinate system (usually along acceleration for one axis, perpendicular for the other).
  • For multi-body problems, write separate equations for each body and solve.
  • Remember: static friction adjusts up to μsN; if 'just about to move' implies maximum static.
  • Practice pulley and wedge problems – they are NEET favorites.

❓ Frequently asked questions

📌 What is the difference between static and kinetic friction?
Static friction acts when there is no relative motion, and its magnitude can vary from 0 to μsN. Kinetic friction acts during motion and is constant (μkN).
📌 Can a body move in the direction opposite to net force?
No. According to Newton's second law, acceleration is always in the direction of net force. However, velocity can be opposite (deceleration).
📌 When do we use the formula T = 2m₁m₂g/(m₁+m₂)?
For an Atwood machine (two masses hanging over a frictionless pulley), this gives tension in the string. It assumes massless string and ideal pulley.
📌 How to find direction of friction on an inclined plane?
Friction opposes relative motion or tendency. If block tends to slide down, friction acts up the incline; if an external force pushes it up, friction acts down.

⚡ Master Laws of Motion – the gateway to solving mechanics problems. Bookmark this page for last‑minute revision.

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